Merge remote-tracking branch 'origin/master'

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@ -302,7 +302,7 @@
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@ -510,7 +510,7 @@ For the implementation of the above inertia force components, each substructure
为了实现上述惯性力分量每个子结构对象必须提供一个函数计算方程1.221.291.311.331.35)中蓝色标记的所有标量、矢量和矩阵。其中一些具有物理意义,例如子结构的总质量 $M$、当前的重心 $\boldsymbol{\mathsf{r}}_{c g}$ 及其对一阶和二阶自由度导数 $(\mathsf{r}_{c g,q_{i}}\ a n d\ r_{c g,q_{i}q_{j}})$以及由1.23)给出的当前转动惯量分量矩阵 $I_{b a s e}$。其余标量可以简化为子结构上的两个独特的体积积分,它们是局部质量矩阵和非线性陀螺矩阵的条目:
$$
m_{i j}^{11}=\int_{\mathcal{V}}\rho\,\mathbf{r}_{1,q_{i}}^{T}\mathbf{r}_{1,q_{j}}d\mathcal{V}\;\;\mathbf{a}\mathsf{n}\mathsf{d}\;\;h_{i j k}^{111}=\int_{\mathcal{V}}\rho\,\mathbf{r}_{1,q_{i}}^{T}\mathbf{r}_{1,q_{j}q_{k}}d\mathcal{V}
m_{i j}^{11}=\int_{\mathcal{V}}\rho\,\mathbf{r}_{1,q_{i}}^{T}\mathbf{r}_{1,q_{j}}d\mathcal{V}\;\;\mathbf{a}\mathsf{n}\mathsf{d}\;\;h_{i j k}^{111}=\int_{\mathcal{V}}\rho\,\mathbf{r}_{1,q_{i}}^{T}\mathbf{r}_{1,q_{j}q_{k}}d\mathcal{V}\tag{1.36}
$$
for all $i,j,k\,\in\,{\bf d}_{b}$ where ${\mathfrak{d}}_{b}$ is the DOF index vector for the substructure $b$ . The remaining matrices can be reduced to these three unique volume integrals over the substructure:
@ -518,7 +518,7 @@ for all $i,j,k\,\in\,{\bf d}_{b}$ where ${\mathfrak{d}}_{b}$ is the DOF index ve
对于所有 $i,j,k\,\in\,{\bf d}_{b}$,其中 ${\mathfrak{d}}_{b}$ 是子结构 $b$ 的自由度 (DOF) 索引向量。剩余的矩阵可以简化为子结构上的这三个独特的体积积分:
$$
\mathsf{A}_{b a s e,i}\equiv\int_{\mathcal{V}}\mathsf{r}_{1,q_{i}}\mathsf{r}_{1}^{T}d\mathcal{V}\;,\;\;\mathsf{A}_{b a s e,1,i j}\equiv\int_{\mathcal{V}}\rho\,\mathsf{r}_{1,q_{j}}\mathsf{r}_{1,q_{i}}^{T}d\mathcal{V}\;\;\mathrm{and}\;\;\mathsf{A}_{b a s e,2,i j}\equiv\int_{\mathcal{V}}\rho\,\mathsf{r}_{1,q_{i},q_{j}}\mathsf{r}_{1}^{T}d\mathcal{V}
\mathsf{A}_{b a s e,i}\equiv\int_{\mathcal{V}}\mathsf{r}_{1,q_{i}}\mathsf{r}_{1}^{T}d\mathcal{V}\;,\;\;\mathsf{A}_{b a s e,1,i j}\equiv\int_{\mathcal{V}}\rho\,\mathsf{r}_{1,q_{j}}\mathsf{r}_{1,q_{i}}^{T}d\mathcal{V}\;\;\mathrm{and}\;\;\mathsf{A}_{b a s e,2,i j}\equiv\int_{\mathcal{V}}\rho\,\mathsf{r}_{1,q_{i},q_{j}}\mathsf{r}_{1}^{T}d\mathcal{V}\tag{1.37}
$$
for all $i,j\in{\bf d}_{b}$ . Note that the following symmetry rules apply: ${\pmb{\mathsf{A}}}_{b a s e,2,j i}={\pmb{\mathsf{A}}}_{b a s e,2,i j}$ and $\mathbf{A}_{b a s e,1,j i}=\mathbf{A}_{b a s e,1,i j}^{T}$
@ -563,7 +563,7 @@ The following sections contain
The position vector of particles on the rigid body is purely a function of the local spacial coordinates
刚体上质点的位置矢量纯粹是局部空间坐标的函数
$$
\mathbf{r}_{1,b}=\left\{\begin{array}{l}{x}\\ {y}\\ {z}\end{array}\right\}
\mathbf{r}_{1,b}=\left\{\begin{array}{l}{x}\\ {y}\\ {z}\end{array}\right\}\tag{1.38}
$$
where $(x,y,z)\in\mathcal{V}$
@ -574,93 +574,117 @@ The nonlinear co­rotational finite beam element methodology used for this type
用于此类子结构的非线性同向旋转有限梁单元方法在附录A中详细描述。该方法与Crisfield和Krenk的方法类似不同之处在于非线性几何公式是显式的即单元坐标系和节点的局部小旋转被表示为全局节点自由度的显式非线性函数。单元的弹性变形和柔度则改编自Krenk和Couturier提出的平衡单元。
A co­rotational beam substructure consists of finite beam elements with two end-­nodes having six DOFs: three translations and three rotations (using Rodrigues parameters) in the substructure coordinate system. The DOF vector of the substructure
一种共转动梁子结构由有两个端节点的有限梁单元组成在子结构坐标系中每个端节点具有六个自由度DOFs三个平移和三个旋转使用罗德里格斯参数。该子结构的自由度向量如下
# Inertia forces
### Inertia forces
The volume integral over a co­rotational beam substructure can be computed as the sum of integrals over the volume $\mathcal{V}_{n}$ of element $n$ , here generically written as
共旋梁子结构上的体积积分可以计算为单元 $n$ 的体积 $\mathcal{V}_{n}$ 上的积分之和,这里通常写为
$$
\int_{\mathcal{V}}\left(\mathbf{\Phi}\right)d\mathcal{V}=\sum_{n=1}^{N_{e,b}}\int_{\mathcal{V}_{n}}\left(\mathbf{\Phi}\right)d\mathcal{V}_{n}=\sum_{n=1}^{N_{e,b}}\left(\frac{l_{n}}{2}\int_{-1}^{1}\int_{\mathcal{A}}\left(\mathbf{\Phi}\right)d\mathcal{A}d\zeta\right)
\int_{\mathcal{V}}\left(\right)d\mathcal{V}=\sum_{n=1}^{N_{e,b}}\int_{\mathcal{V}_{n}}\left(\right)d\mathcal{V}_{n}=\sum_{n=1}^{N_{e,b}}\left(\frac{l_{n}}{2}\int_{-1}^{1}\int_{\mathcal{A}}\left(\right)d\mathcal{A}d\zeta\right)\tag{1.39}
$$
where each volume integral over the element of initial length $l_{n}$ are split into an area integral over each cross­ section and a line integral over the non­dimensional element coordinate $\zeta$ from the mid­point to the end nodes at $\zeta=\pm1$ .
The position vector of particles on element number $n$ is
其中,初始长度为$l_{n}$的单元上的每个体积积分都被分解为每个横截面上的面积积分,以及从单元中点到$\zeta=\pm1$处端节点的无量纲单元坐标$\zeta$上的线积分。
单元n上质点的位置向量为
$$
\mathbf{r}_{1,b,n}=\mathbf{r}_{\mathrm{mid},b,n}\left(\mathbf{q}_{b,n}\right)+\mathbf{E}_{b,n}\left(\mathbf{q}_{b,n}\right)\mathbf{v}_{b,n}\left(\mathbf{q}_{b,n};x,y,\zeta\right)
\mathbf{r}_{1,b,n}=\mathbf{r}_{\mathrm{mid},b,n}\left(\mathbf{q}_{b,n}\right)+\mathbf{E}_{b,n}\left(\mathbf{q}_{b,n}\right)\mathbf{v}_{b,n}\left(\mathbf{q}_{b,n};x,y,\zeta\right)\tag{1.40}
$$
where ${\boldsymbol{\mathsf{r}}}_{{\boldsymbol{\mathsf{m i d}}},{\boldsymbol{b}},n}$ is a vector from the substructure base to the mid­point of the element linearly dependent on the displacement DOFs of element nodes, $\mathsf{E}_{b,n}$ is the element coordinate system dependent on all twelve nodal DOFs $\mathbf{q}_{b,n}$ of element $n$ , and the cross­sectional displacement vector is given by
where ${\boldsymbol{\mathsf{r}}}_{{\boldsymbol{\mathsf{m i d}}},{\boldsymbol{b}},n}$ is a vector from the substructure base to the mid­point of the element linearly dependent on the displacement DOFs of element nodes, $\mathsf{E}_{b,n}$ is the element coordinate system dependent on all twelve nodal DOFs $\mathbf{q}_{b,n}$ of element $n$ , and the cross-­sectional displacement vector is given by
其中, ${\boldsymbol{\mathsf{r}}}_{{\boldsymbol{\mathsf{m i d}}},{\boldsymbol{b}},n}$ 是从子结构基座到单元中点的向量,其线性依赖于单元节点的位移自由度,$\mathsf{E}_{b,n}$ 是依赖于单元 $n$ 的所有十二个节点自由度 $\mathbf{q}_{b,n}$ 的单元坐标系,横截面位移向量由下式给出
$$
\begin{array}{r}{\mathbf{v}_{b,n}=\left\{\begin{array}{c}{x}\\ {y}\\ {\frac{1}{2}l_{n}\zeta}\end{array}\right\}+\left\{\begin{array}{c}{u_{x,n}(\zeta)}\\ {u_{y,n}(\zeta)}\\ {u_{z,n}(\zeta)}\end{array}\right\}+\left[\begin{array}{c c c}{0}&{-\theta_{z,n}(\zeta)}&{\theta_{y,n}(\zeta)}\\ {\theta_{z,n}(\zeta)}&{0}&{-\theta_{x,n}(\zeta)}\\ {-\theta_{y,n}(\zeta)}&{\theta_{x,n}(\zeta)}&{0}\end{array}\right]\left\{\begin{array}{c}{x}\\ {y}\\ {0}\end{array}\right\}}\end{array}
\begin{array}{r}{\mathbf{v}_{b,n}=\left\{\begin{array}{c}{x}\\ {y}\\ {\frac{1}{2}l_{n}\zeta}\end{array}\right\}+\left\{\begin{array}{c}{u_{x,n}(\zeta)}\\ {u_{y,n}(\zeta)}\\ {u_{z,n}(\zeta)}\end{array}\right\}+\left[\begin{array}{c c c}{0}&{-\theta_{z,n}(\zeta)}&{\theta_{y,n}(\zeta)}\\ {\theta_{z,n}(\zeta)}&{0}&{-\theta_{x,n}(\zeta)}\\ {-\theta_{y,n}(\zeta)}&{\theta_{x,n}(\zeta)}&{0}\end{array}\right]\left\{\begin{array}{c}{x}\\ {y}\\ {0}\end{array}\right\}}\end{array}\tag{1.41}
$$
where $x,y$ are the coordinates of the cross­section and the cross­sectional translations and (small) rotations are given by the shape function polynomials
where $x,y$ are the coordinates of the cross-­section and the cross-­sectional translations and (small) rotations are given by the shape function polynomials
其中 $x,y$ 是截面坐标,截面平移和(小)转动由形函数多项式给出
$$
\left\{\begin{array}{l}{u_{x,n}}\\ {u_{y,n}}\\ {u_{z,n}}\\ {\theta_{x,n}}\\ {\theta_{y,n}}\\ {\theta_{z,n}}\end{array}\right\}=\sum_{p=0}^{P+3}\mathbf{N}_{n,p}\,\mathbf{g}\left(\mathbf{q}_{b,n}\right)\zeta^{p}=\sum_{p=0}^{P+3}\left[\begin{array}{l}{\bar{\mathbf{N}}_{n,p}}\\ {\tilde{\mathbf{N}}_{n,p}}\end{array}\right]\mathbf{g}\left(\mathbf{q}_{b,n}\right)\zeta^{p}
\left\{\begin{array}{l}{u_{x,n}}\\ {u_{y,n}}\\ {u_{z,n}}\\ {\theta_{x,n}}\\ {\theta_{y,n}}\\ {\theta_{z,n}}\end{array}\right\}=\sum_{p=0}^{P+3}\mathbf{N}_{n,p}\,\mathbf{g}\left(\mathbf{q}_{b,n}\right)\zeta^{p}=\sum_{p=0}^{P+3}\left[\begin{array}{l}{\bar{\mathbf{N}}_{n,p}}\\ {\tilde{\mathbf{N}}_{n,p}}\end{array}\right]\mathbf{g}\left(\mathbf{q}_{b,n}\right)\zeta^{p}\tag{1.42}
$$
where $\aleph_{n,p}$ are the $6\uptimes7$ coefficient matrices of the local shape functions, $P$ is the polynomial order of the element properties (e.g. for prismatic elements $P=0$ ), and $\mathfrak{g}$ is the nonlinear $7\times1$ vector function of the twelve nodal DOFs. In the following, we split the local shape function coefficient matrix into two, one $3\mathrm{x7}$ matrix for the displacements $\bar{\aleph}_{n,p}$ and another 3x7 matrix for the rotations $\tilde{\mathsf{N}}_{n,p}$ .
where $\mathsf{N}_{n,p}$ are the $6\times7$ coefficient matrices of the local shape functions, $P$ is the polynomial order of the element properties (e.g. for prismatic elements $P=0$ ), and $\mathfrak{g}$ is the nonlinear $7\times1$ vector function of the twelve nodal DOFs. In the following, we split the local shape function coefficient matrix into two, one $3\times7$ matrix for the displacements $\bar{\mathsf{N}}_{n,p}$ and another $3\times7$ matrix for the rotations $\tilde{\mathsf{N}}_{n,p}$ .
This form of the cross­sectional displacement vector is inconvenient for the isolation of the spacial variables $x,y,\zeta$ . We therefore rewrite it as
This form of the cross-­sectional displacement vector is inconvenient for the isolation of the spacial variables $x,y,\zeta$ . We therefore rewrite it as
其中 $\mathsf{N}_{n,p}$ 是局部形状函数的 $6\times7$ 系数矩阵,$P$ 是单元属性的多项式阶数(例如,对于棱柱单元 $P=0$${g}$ 是十二个节点自由度的非线性 $7\times1$ 向量函数。在下文中,我们将局部形状函数系数矩阵分为两个,一个用于位移的 $3\times7$ 矩阵 $\bar{\mathsf{N}}_{n,p}$ 和另一个用于旋转的 $3\times7$ 矩阵 $\tilde{\mathsf{N}}_{n,p}$。
这种形式的横截面位移向量不便于分离空间变量 $x,y,\zeta$。因此,我们将其改写为
$$
\begin{array}{r}{\mathbf{v}_{b,n}=\left\{\begin{array}{c}{x}\\ {y}\\ {\frac{1}{2}l_{n}\zeta}\end{array}\right\}+\displaystyle\sum_{p=0}^{P+3}\left\{\begin{array}{c}{u_{x,n,p}}\\ {u_{y,n,p}}\\ {u_{z,n,p}}\end{array}\right\}\zeta^{p}+\displaystyle\sum_{p=0}^{P+3}\left(\left\{\begin{array}{c}{0}\\ {\theta_{z,n,p}}\\ {-\theta_{y,n,p}}\end{array}\right\}x+\left\{\begin{array}{c}{-\theta_{z,n,p}}\\ {0}\\ {\theta_{x,n,p}}\end{array}\right\}y\right)\zeta^{p}}\end{array}
\begin{array}{r}{\mathbf{V}_{b,n}=\left\{\begin{array}{c}{x}\\ {y}\\ {\frac{1}{2}l_{n}\zeta}\end{array}\right\}+\displaystyle\sum_{p=0}^{P+3}\left\{\begin{array}{c}{u_{x,n,p}}\\ {u_{y,n,p}}\\ {u_{z,n,p}}\end{array}\right\}\zeta^{p}+\displaystyle\sum_{p=0}^{P+3}\left(\left\{\begin{array}{c}{0}\\ {\theta_{z,n,p}}\\ {-\theta_{y,n,p}}\end{array}\right\}x+\left\{\begin{array}{c}{-\theta_{z,n,p}}\\ {0}\\ {\theta_{x,n,p}}\end{array}\right\}y\right)\zeta^{p}}\end{array}\tag{1.43}
$$
where the polynomial coefficients of the cross­sectional displacements and rotations are given by
where the polynomial coefficients of the cross­-sectional displacements and rotations are given by
其中截面位移和转角的多项式系数由下式给出
$$
\left\{\begin{array}{c}{u_{x,n,p}}\\ {u_{y,n,p}}\\ {u_{z,n,p}}\end{array}\right\}=\bar{\aleph}_{n,p}\,\mathbf{g}\left(\mathbf{q}_{b,n}\right)\quad\mathsf{a n d}\quad\left\{\begin{array}{c}{\theta_{x,n,p}}\\ {\theta_{y,n,p}}\\ {\theta_{z,n,p}}\end{array}\right\}=\tilde{\aleph}_{n,p}\mathbf{g}\left(\mathbf{q}_{b,n}\right)
\left\{\begin{array}{c}{u_{x,n,p}}\\ {u_{y,n,p}}\\ {u_{z,n,p}}\end{array}\right\}=\bar{\mathsf{N}}_{n,p}\,\mathbf{g}\left(\mathbf{q}_{b,n}\right)\quad\mathsf{a n d}\quad\left\{\begin{array}{c}{\theta_{x,n,p}}\\ {\theta_{y,n,p}}\\ {\theta_{z,n,p}}\end{array}\right\}=\tilde{\mathsf{N}}_{n,p}\mathbf{g}\left(\mathbf{q}_{b,n}\right)\tag{1.44}
$$
that depend on the nodal DOFs of the element.
取决于单元的节点自由度。
Using (1.43) with (1.42), the position vector for element $n$ on substructure $b$ (1.40) can be rewritten as
$$
\mathbf{r}_{1,b,n}=\sum_{p=0}^{P+3}\left(\mathbf{r}_{o,b,n,p}+x\,\mathbf{r}_{x,b,n,p}+y\,\mathbf{r}_{y,b,n,p}\right)\zeta^{p}
\mathbf{r}_{1,b,n}=\sum_{p=0}^{P+3}\left(\mathbf{r}_{o,b,n,p}+x\,\mathbf{r}_{x,b,n,p}+y\,\mathbf{r}_{y,b,n,p}\right)\zeta^{p}\tag{1.45}
$$
where the sub­vectors are
where the sub-­vectors are
$$
\begin{array}{r l}&{\mathbf{r}_{o,b,n,p}\left(\mathbf{q}_{b,n}\right)=\pmb{\Sigma}_{b,n}\left(\mathbf{q}_{b,n}\right)\,\bar{\mathbf{N}}_{n,p}\,\mathbf{g}\left(\mathbf{q}_{b,n}\right)+\delta_{0p}\,\mathbf{r}_{\mathrm{mid},b,n}\left(\mathbf{q}_{b,n}\right)+\delta_{1p}\,\frac{l_{n}}{2}\mathbf{e}_{3,b,n}\left(\mathbf{q}_{b,n}\right)}\\ &{\mathbf{r}_{x,b,n,p}\left(\mathbf{q}_{b,n}\right)=\pmb{\Sigma}_{b,n}\left(\mathbf{q}_{b,n}\right)\,\mathbf{P}_{x}\,\tilde{\mathbf{N}}_{n,p}\,\mathbf{g}\left(\mathbf{q}_{b,n}\right)+\delta_{0p}\,\mathbf{e}_{1,b,n}\left(\mathbf{q}_{b,n}\right)}\\ &{\mathbf{r}_{y,b,n,p}\left(\mathbf{q}_{b,n}\right)=\pmb{\Sigma}_{b,n}\left(\mathbf{q}_{b,n}\right)\,\mathbf{P}_{y}\,\tilde{\mathbf{N}}_{n,p}\,\mathbf{g}\left(\mathbf{q}_{b,n}\right)+\delta_{0p}\,\mathbf{e}_{2,b,n}\left(\mathbf{q}_{b,n}\right)}\end{array}
$$
{\mathbf{r}_{o,b,n,p}\left(\mathbf{q}_{b,n}\right)={\mathbf{E}}_{b,n}\left(\mathbf{q}_{b,n}\right)\,\bar{\mathbf{N}}_{n,p}\,\mathbf{g}\left(\mathbf{q}_{b,n}\right)+\delta_{0p}\,\mathbf{r}_{\mathrm{mid},b,n}\left(\mathbf{q}_{b,n}\right)+\delta_{1p}\,\frac{l_{n}}{2}\mathbf{e}_{3,b,n}\left(\mathbf{q}_{b,n}\right)}\tag{1.46a}
$$
$$
{\mathbf{r}_{x,b,n,p}\left(\mathbf{q}_{b,n}\right)=\mathbf{E}_{b,n}\left(\mathbf{q}_{b,n}\right)\,\mathbf{P}_{x}\,\tilde{\mathbf{N}}_{n,p}\,\mathbf{g}\left(\mathbf{q}_{b,n}\right)+\delta_{0p}\,\mathbf{e}_{1,b,n}\left(\mathbf{q}_{b,n}\right)}\tag{1.46b}
$$
$$
{\mathbf{r}_{y,b,n,p}\left(\mathbf{q}_{b,n}\right)=\mathbf{E}_{b,n}\left(\mathbf{q}_{b,n}\right)\,\mathbf{P}_{y}\,\tilde{\mathbf{N}}_{n,p}\,\mathbf{g}\left(\mathbf{q}_{b,n}\right)+\delta_{0p}\,\mathbf{e}_{2,b,n}\left(\mathbf{q}_{b,n}\right)}\tag{1.46c}
$$
where $\delta_{i j}$ is Kroneckers delta which is 1 for $i=j$ , and otherwise 0. Matrices $\mathsf{P}_{x}$ and $\mathsf{P}_{y}$ are constant permutation matrices:
其中 $\delta_{i j}$ 是克罗内克函数,当 $i=j$ 时为1否则为0。矩阵 $\mathsf{P}_{x}$ 和 $\mathsf{P}_{y}$ 是常数置换矩阵:
$$
\begin{array}{r}{\mathsf{P}_{x}=\left[\begin{array}{c c c}{0}&{0}&{0}\\ {0}&{0}&{1}\\ {0}&{-1}&{0}\end{array}\right]\quad\mathsf{a n d}\quad\mathsf{P}_{y}=\left[\begin{array}{c c c}{0}&{0}&{-1}\\ {0}&{0}&{0}\\ {1}&{0}&{0}\end{array}\right]}\end{array}
\begin{array}{r}{\mathsf{P}_{x}=\left[\begin{array}{c c c}{0}&{0}&{0}\\ {0}&{0}&{1}\\ {0}&{-1}&{0}\end{array}\right]\quad\mathsf{a n d}\quad\mathsf{P}_{y}=\left[\begin{array}{c c c}{0}&{0}&{-1}\\ {0}&{0}&{0}\\ {1}&{0}&{0}\end{array}\right]}\end{array}\tag{1.47}
$$
Note that $\mathsf{P}_{x}$ and $\mathsf{P}_{y}$ are equal to the matrix $\boldsymbol{\mathsf{N}}$ in Eq. (E.3) related to the angular derivative of a rotation matrix with a constant unit­vectors in the $x$ ­ and $y$ ­directions, respectively.
Note that $\mathsf{P}_{x}$ and $\mathsf{P}_{y}$ are equal to the matrix $\boldsymbol{\mathsf{N}}$ in Eq. (E.3) related to the angular derivative of a rotation matrix with a constant unit-­vectors in the $x$ ­ and $y$ ­directions, respectively.
In the following, the element­index $n$ and the substructure­index $b$ are omitted for brevity.
In the following, the element-­index $n$ and the substructure-­index $b$ are omitted for brevity.
Integration over the cross­sectional area spanned by $x$ and $y$ of the element coordinate system are defined by the mass per unit­length $m$ , the center of gravity coordinates $x_{c g}$ and $y_{c g}$ , and the moments of inertia about the $x$ ­ and $y$ ­axes and their cross­coupling. These cross­sectional properties are given by polynomials to the order of $P$ along the element lengthwise coordinate $\zeta\in[-1,1]$ as
Integration over the cross­-sectional area spanned by $x$ and $y$ of the element coordinate system are defined by the mass per unit­­-length $m$ , the center of gravity coordinates $x_{c g}$ and $y_{c g}$ , and the moments of inertia about the $x$ ­ and $y$ ­axes and their cross­­-coupling. These cross­­-sectional properties are given by polynomials to the order of $P$ along the element lengthwise coordinate $\zeta\in[-1,1]$ as
请注意,$\mathsf{P}_{x}$ 和 $\mathsf{P}_{y}$ 等于方程 (E.3) 中的矩阵 $\boldsymbol{\mathsf{N}}$,该矩阵分别与旋转矩阵在 $x$ 和 $y$ 方向上具有常量单位向量的角导数相关。
在下文中,为了简洁,省略了单元索引 $n$ 和子结构索引 $b$。
单元坐标系中由 $x$ 和 $y$ 构成的截面面积上的积分由单位长度质量 $m$、重心坐标 $x_{c g}$ 和 $y_{c g}$、以及绕 $x$ 轴和 $y$ 轴的转动惯量及其交叉耦合定义。这些截面特性由沿着单元长度坐标 $\zeta\in[-1,1]$ 的 $P$ 阶多项式给出,如下所示:
$$
\begin{array}{l}{\displaystyle\int_{A}\rho\,d A=\sum_{r=0}^{P}a_{m,r}\,\zeta^{r}\;,\;\;\int_{A}\rho x\,d A=\sum_{r=0}^{P}a_{m x_{c g},r}\,\zeta^{r}\;,\;\;\int_{A}\rho y\,d A=\sum_{r=0}^{P}a_{m y_{c g},r}\,\zeta^{r}\;,}\\ {\displaystyle\int_{A}\rho x^{2}\,d A=\sum_{r=0}^{P}a_{I_{x x},r}\,\zeta^{r}\;,\;\;\displaystyle\int_{A}\rho y^{2}\,d A=\sum_{r=0}^{P}a_{I_{y y},r}\,\zeta^{r}\;,\;\;\displaystyle\int_{A}\rho x y\,d A=\sum_{r=0}^{P}a_{I_{x y},r}\,\zeta^{r}}\end{array}
\begin{array}{l}{\displaystyle\int_{A}\rho\,d A=\sum_{r=0}^{P}a_{m,r}\,\zeta^{r}\;,\;\;\int_{A}\rho x\,d A=\sum_{r=0}^{P}a_{m x_{c g},r}\,\zeta^{r}\;,\;\;\int_{A}\rho y\,d A=\sum_{r=0}^{P}a_{m y_{c g},r}\,\zeta^{r}\;,}\\ {\displaystyle\int_{A}\rho x^{2}\,d A=\sum_{r=0}^{P}a_{I_{x x},r}\,\zeta^{r}\;,\;\;\displaystyle\int_{A}\rho y^{2}\,d A=\sum_{r=0}^{P}a_{I_{y y},r}\,\zeta^{r}\;,\;\;\displaystyle\int_{A}\rho x y\,d A=\sum_{r=0}^{P}a_{I_{x y},r}\,\zeta^{r}}\end{array}\tag{1.48}
$$
where the polynomial coefficients are generated from the model input in a pre­simulation processing step. The coefficients $a_{m x_{c g},r}$ and $a_{m y_{c g},r}$ represent a polynomial fit to the product of the mass per unit­length $m$ and the individual center of gravity coordinates $x_{c g}$ and $y_{c g}$ in the element coordinate system.
where the polynomial coefficients are generated from the model input in a pre­-simulation processing step. The coefficients $a_{m x_{c g},r}$ and $a_{m y_{c g},r}$ represent a polynomial fit to the product of the mass per unit-­length $m$ and the individual center of gravity coordinates $x_{c g}$ and $y_{c g}$ in the element coordinate system.
Integration over an element with the local position vector (1.45) and using (1.48), the mass of the element can be computed as
其中多项式系数是在预仿真处理步骤中从模型输入生成的。系数 $a_{m x_{c g},r}$ 和 $a_{m y_{c g},r}$ 表示对单位长度质量 $m$ 与单元坐标系中单个重心坐标 $x_{c g}$ 和 $y_{c g}$ 乘积的多项式拟合。
对具有局部位置矢量 (1.45) 的单元进行积分并使用 (1.48),可以计算出单元的质量为
$$
M=\frac{l}{2}\sum_{r=0}^{P}c(r)a_{m,r}
M=\frac{l}{2}\sum_{r=0}^{P}c(r)a_{m,r}\tag{1.49}
$$
where the coefficient function is given by
$$
c\left(r\right)={\frac{\left(-1\right)^{r}+1}{1+r}}={\left\{\begin{array}{l l}{2/(1+r)}&{r\;\;{\mathsf{e v e n}}}\\ {\;\;\;\;0}&{r\;\;\;{\mathsf{o d d}}}\end{array}\right.}
c\left(r\right)={\frac{\left(-1\right)^{r}+1}{1+r}}={\left\{\begin{array}{l l}{2/(1+r)}&{r\;\;{\mathsf{e v e n}}}\\ {\;\;\;\;0}&{r\;\;\;{\mathsf{o d d}}}\end{array}\right.}\tag{1.50}
$$
The element center of gravity position times the element mass and the nodal derivatives can be computed as
单元重心位置乘以单元质量和节点导数可以计算为
$$
\begin{array}{l l}{{\displaystyle M\,{\bf r}_{c g}=\frac{l}{2}\sum_{p=0}^{P+3}\left(\sum_{r=0}^{P}c(p+r)\left(a_{m,r}\,{\bf r}_{o,p}+a_{m x_{c g},r}\,{\bf r}_{x,p}+a_{m y_{c g},r}\,{\bf r}_{y,p}\right)\right)}}\\ {{\displaystyle M\,{\bf r}_{c g,q_{i}}=\frac{l}{2}\sum_{p=0}^{P+3}\left(\sum_{r=0}^{P}c(p+r)\left(a_{m,r}\,{\bf r}_{o,p,q_{i}}+a_{m x_{c g},r}\,{\bf r}_{x,p,q_{i}}+a_{m y_{c g},r}\,{\bf r}_{y,p,q_{i}}\right)\right)}}\\ {{\displaystyle M\,{\bf r}_{c g,q_{i},q_{j}}=\frac{l}{2}\sum_{p=0}^{P+3}\left(\sum_{r=0}^{P}c(p+r)\left(a_{m,r}\,{\bf r}_{o,p,q_{i},q_{j}}+a_{m x_{c g},r}\,{\bf r}_{x,p,q_{i},q_{j}}+a_{m y_{c g},r}\,{\bf r}_{y,p,q_{i},q_{j}}\right)\right)}}\end{array}

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@ -6,7 +6,7 @@
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{"id":"505acb3e6b119076","type":"text","text":"# 6月已完成\n\n\nP1 结果对比\n- Herowind 带3.5气动与fast3.5对比 相同\n- Herowind 带4.0气动与fast4.0对比 相同\n- Herowind 带hrl气动与fast对比 需气动支持15MW\n- 叶根坐标系转换 \n\t- 叶尖变形量 - 变形向量 dot product 叶根坐标系方向\n\t- 叶片载荷输入量呢 载荷传递在blade mesh.force momentmesh.orientation = coord_sys.n\n\nP1 Bladed交流问题汇总\n\nP1 模型线性化原理 done\n- Bladed 线性化理论手册 仔细阅读\n- multibody blade transform\n- fast线性化理论\n- 梳理Bladed线性化方法框架\n\n\nP1 编写线性化理论手册 done\nP1 上手Bladed \\ fast 线性化功能研究OpenFAST线性化实现原理 done","x":-700,"y":134,"width":440,"height":560},
{"id":"30cb7486dc4e224c","type":"text","text":"# 8月已完成\n\n","x":260,"y":134,"width":440,"height":560},
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{"id":"c18d25521d773705","type":"text","text":"# 计划\n这周要做的3~5件重要的事情这些事情能有效推进实现OKR。\n\nP1 必须做。P2 应该做\n\n\nP2 柔性部件 叶片、塔架变形算法 主线\n- 变形体动力学 简略看看ing\n- 柔性梁弯曲变形振动学习,主线 \n\t- 广义质量 刚度矩阵及含义\n\t\n- 梳理bladed动力学框架\n\t- 子结构文献阅读\n\t- 叶片模型建模 done\n- 共旋方法学习\n- DTU 变形量计算方法学习\n\n\nP1 线性化方法编写 搁置\n\nP1 控制调通\n- 测试编译方案 搁置\n- 上传git done\n- 编写传递逻辑\n\nP1 bladed多体参数梳理\n\nP1 湍流 气动 多体 控制联调\n\nP1 bladed对比--产出报告\n- 稳态变形量对比 -- steady power production loading、steady parked loading\n\n\nP2 如何优雅的存储、输出结果。\nP2 yaw 自由度再bug确认 已知原理了\n","x":-597,"y":-693,"width":453,"height":347}
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